Boris Borcic wrote:
Gerard flanagan wrote:
George Sakkis wrote:
..
Note that this works correctly only if the versions are already sorted
by major version.
Yes, I should have mentioned it. Here's a fuller example below.
There's maybe better ways of sorting version numbers, but this is what
I do.
Indeed, your sort takes George's objection too litterally, what's needed
for a correct endresult is only that major versions be grouped together,
and this is most simply obtained by sorting the input data in (default)
string order, is it not ?
Yes, I see what you mean - the fact that a default sort orders "1.10"
before "1.9" doesn't actually matter for the required result.
datadict = \
dict((k, len(list(g))) for k,g in groupby(data, lambda s: s[:3]))
And, s[:3] is wrong. So:
data.sort()
datadict = \
dict((k, len(list(g))) for k,g in groupby(data, lambda s:
'.'.join(s.split('.',2)[:2])))
should work, I hope.
Cheers,
Gerard
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