George Sakkis wrote:
On Sep 18, 11:43 am, Gerard flanagan <[EMAIL PROTECTED]> wrote:
Simon Mullis wrote:
Hi,
Let's say I have an arbitrary list of minor software versions of an
imaginary software product:
l = [ "1.1.1.1", "1.2.2.2", "1.2.2.3", "1.3.1.2", "1.3.4.5"]
I'd like to create a dict with major_version : count.
(So, in this case:
dict_of_counts = { "1.1" : "1",
"1.2" : "2",
"1.3" : "2" }
[...]
data = [ "1.1.1.1", "1.2.2.2", "1.2.2.3", "1.3.1.2", "1.3.4.5"]
from itertools import groupby
datadict = \
dict((k, len(list(g))) for k,g in groupby(data, lambda s: s[:3]))
print datadict
Note that this works correctly only if the versions are already sorted
by major version.
Yes, I should have mentioned it. Here's a fuller example below. There's
maybe better ways of sorting version numbers, but this is what I do.
data = [ "1.2.2.2", "1.2.2.3", "1.3.1.2", "1.1.1.1", "1.3.14.5",
"1.3.21.6" ]
from itertools import groupby
import re
RXBUILDSORT = re.compile(r'\d+|[a-zA-Z]')
def versionsort(s):
key = []
for part in RXBUILDSORT.findall(s.lower()):
try:
key.append(int(part))
except ValueError:
key.append(ord(part))
return tuple(key)
data.sort(key=versionsort)
print data
datadict = \
dict((k, len(list(g))) for k,g in groupby(data, lambda s: s[:3]))
print datadict
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