Where exactly should i call ServerProxy? Following is the code from my
client.py
t = SecureTransport()
t.set_authorization(ustring, text_ucert)
server = xmlrpclib.Server('http://localhost:8000/',transport=t)
print server.s()
Note: Full code for client is here at http://privatepaste.com/b56oS1Xa7P
and following is my server code
import SimpleXMLRPCServer
#server = ServerProxy("http://betty.userland.com";)
class AuthenticationFunctions:
def s(self):
print "something..."
server = SimpleXMLRPCServer.SimpleXMLRPCServer(("localhost", 8000))
server.register_instance(AuthenticationFunctions())
server.serve_forever()
On Sat, Sep 13, 2008 at 8:44 AM, Fredrik Lundh <[EMAIL PROTECTED]>wrote:
> Usman Ajmal wrote:
>
> Please explain the arguments of send_request. What exactly are the
>> connection, handler and request_body? It will be really helpful if you give
>> an example of how do i call send_request
>>
>
> you don't call send_request. you should pass the SecureTransport instance
> as an argument to the ServerProxy, which will then use it to talk to the
> server. see the "custom transport" example in the library reference that I
> pointed you to.
>
> http://www.python.org/doc/lib/xmlrpc-client-example.html
>
> </F>
>
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> http://mail.python.org/mailman/listinfo/python-list
>
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