Thanks for ur help. But now i am getting an error xmlrpclib.ProtocolError: <ProtocolError for localhost:8000/RPC2: 500 Internal Server Error>
Here is my code at http://privatepaste.com/d81Kut9AFj Any idea what wrong am i doing? On Thu, Sep 11, 2008 at 7:18 AM, Fredrik Lundh <[EMAIL PROTECTED]>wrote: > Usman Ajmal wrote: > > And i also fount that a typical system.auth call will look like: >> >> POST /xmlrpc/clarens_server.py HTTP/1.0 >> Host: localhost >> User-Agent: xmlrpclib.py/0.9.9 (by www.pythonware.com < >> http://www.pythonware.com>) >> >> Content-Type: text/xml >> Content-Length: 105 >> AUTHORIZATION: Basic MkhVTm9VazYxbXArVEZLS0dCY2tIRlA3bjVzPQo6RnJvbSBi >> <?xml version='1.0'?> >> <methodCall> >> <methodName>system.auth</methodName> >> >> <params> >> </params> >> </methodCall> >> >> >> Problem is that i don't know how do i generate above xml system.auth call. >> Can anyone please tell me how do call a function, setting the header of the >> call too? >> > > you need to plugin a custom transport. see this page for an example: > > http://www.python.org/doc/lib/xmlrpc-client-example.html > > in your case, it should be sufficient to override send_request, e.g. > (untested): > > class SecureTransport(xmlrpclib.Transport): > > def set_authorization(self, ustring, text_ucert): > self.authoriation = encodestring( > "%s:%s" % (ustring,text_ucert) > ) > > def send_request(self, connection, handler, request_body): > connection.putrequest("POST", handler) > connection.putheader("Authorization", > "Basic %s" % self.authorization > ) > > and instantiate the transport by doing > > t = SecureTransport() > t.set_authorization(ustring, text_ucert) > > before passing to the server proxy. > > </F> > > -- > http://mail.python.org/mailman/listinfo/python-list >
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