On Wed, 2008-07-30 at 14:08 -0700, [EMAIL PROTECTED] wrote: > On 29 Jul., 01:05, Raymond Hettinger <[EMAIL PROTECTED]> wrote: > > [Ervan Ensis] > > > > > I have a list like [108, 58, 68]. I want to return > > > the sorted indices of these items in the same order > > > as the original list. So I should return [2, 0, 1] > > > > One solution is to think of the list indexes > > being sorted according the their corresponding > > values in the input array: > > > > >>> s = [ 108, 58, 68 ] > > >>> sorted(range(len(s)), key=s.__getitem__) > > > > [1, 2, 0] > > > > To get the desired output you have to apply it twice: > >>> sorted(range(len(s)), key=sorted(range(len(s)), > >>> key=s.__getitem__).__getitem__) > [2, 0, 1] > > Wolfram > -- > http://mail.python.org/mailman/listinfo/python-list
Thanks, I knew I was missing something simpler. -- John Krukoff <[EMAIL PROTECTED]> Land Title Guarantee Company -- http://mail.python.org/mailman/listinfo/python-list
