On Mon, 2008-07-28 at 15:00 -0700, Gary Herron wrote: > Guilherme Polo wrote: > > On Mon, Jul 28, 2008 at 6:24 PM, Ervan Ensis <[EMAIL PROTECTED]> wrote: > > > >> My programming skills are pretty rusty and I'm just learning Python so this > >> problem is giving me trouble. > >> > >> I have a list like [108, 58, 68]. I want to return the sorted indices of > >> these items in the same order as the original list. So I should return [2, > >> 0, 1] > >> > > > > You could simply do this: > > > > a = [108, 58, 68] > > b = sorted(a) > > [b.index(c) for c in a] > > > > Yuck. Slow, and it fails if duplicate list elements exist. > > Also... This looks like a beginners programming assignment. Let's > let him try it himself. We can offer help rather than full solutions if > he has specific Python questions. > > > > > > > > >> For a list that's already in order, I'll just return the indices, i.e. [56, > >> 66, 76] should return [0, 1, 2] > >> > >> Any help would be appreciated. > >> > >> -- > >> http://mail.python.org/mailman/listinfo/python-list > >> > >> > > > > > > > > > > -- > http://mail.python.org/mailman/listinfo/python-list
Sorry, problem was interesting to solve, so I may have jumped the gun. I do wonder why OP was asking for this though, as now that you mention it I can't think of a use case outside of a homework assignment. -- John Krukoff <[EMAIL PROTECTED]> Land Title Guarantee Company -- http://mail.python.org/mailman/listinfo/python-list
