On Sat, Jul 19, 2008 at 10:43 PM, Michael Tobis <[EMAIL PROTECTED]> wrote:
> Can a lambda call itself without giving itself a name?
Kind of. There's a couple ways I know of.
The functional way, which involves the lambda receiving itself as an argument:
(lambda f: f(10, f))(lambda n, f: n and (sys.stdout.write("%d\n" % n)
or f(n-1,f)))
The stack frame examination way:
import sys, inspect, new
(lambda:sys.stdout.write('recurse\n') or
new.function(inspect.currentframe().f_code, globals())())()
The functional way is probably harder to grok unless you've studied
lambda calculus or had experience with "real" functional languages (I
haven't). For fun, try throwing a Y combinator in there.
-Miles
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