oj wrote:
Why not just use * instead of + like:
if re.search(r'^[^LRM]*$', var): # note: ^ outside [] is start of
string; $ means end of string
print "Invalid"
This will *only* print invalid when there is a character other than L,
R, or M or a empty string.
Sorry, forget the beginning and ending markers, I just tried it out, it
doesn't work.
use this instead:
if re.search(r'[^LRM]*', var):
print "Invalid"
No, that's broken.
That searches for any number of invalid characters. Even 0, so it
ALWAYS matches, no matter what string you give it.
My regex worked in the first place, you're complicating it needlessly.
The presence of one invalid character makes the string invalid, so why
not just search for one? Similarly, there's no need to stick in the
beginning and end markers - you're not trying to match the entire
string, just find part of it that is invalid.
However, I think the sets solution by Scott David Daniels is the most
elegant method put forward.
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I see your point after rereading the question, he only wants to match L
R and M
let me revise it please:
To show if valid:
if re.search(r'^[LRM]*$', 'LM'):
print 'Valid'
To show if invalid,
if re.search(r'^[^LRM]*$', '0'):
print 'Inalid'
Example session:
>>> import re
>>> def match(var):
>>> if re.search(r'^[LRM]*$', var):
....... print 'Valid'
....... else:
....... print 'Invalid'
>>>
>>> eg = 'LRLRLRLRLM'
>>> match(eg)
Valid
>>> fg = 'LRLRLRNL'
>>> match(fg)
Invalid
--
Andrew
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