Marcin Krol wrote:
> Hello everyone,
>
> Is there a bug in re.findall in Python 2.4? See:
>
> subnetlist="192.168.100.0 , 192.168.101.0"
> ipre=re.compile("([0-9]{1,3}\.){3}[0-9]{1,3}")
>
> >>> ipre.findall(subnetlist)
>
> ['100.', '101.']
>
>
> But:
>
> a=ipre.finditer(subnetlist)
>
> >>> a.next().group()
> '192.168.100.0'
> >>> a.next().group()
> '192.168.101.0'
> >>> a.next().group()
> Traceback (most recent call last):
> File "<stdin>", line 1, in ?
> StopIteration
>
> Also:
>
> >>> ipre.search(subnetlist).group()
> '192.168.100.0'
>
> Is this a bug or am I doing smth wrong?
>From the doc:
"""
findall( pattern, string[, flags])
Return a list of all non-overlapping matches of pattern in string. If one
or more groups are present in the pattern, return a list of groups; this
will be a list of tuples if the pattern has more than one group.
"""
So findall()'s behaviour changes depending on the number of explicit groups
None:
[m.group() for m in re.finditer(...)]
One:
[m.group(1) for m in re.finditer(...)]
More than one:
[m.groups() for m in re.finditer(...)]
all in accordance with the documentation.
Peter
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