[EMAIL PROTECTED] <[EMAIL PROTECTED]> wrote: > I'm writing to see calcuration process. > And so, I can't catch StopIteration... > > What is mistake? > > def collatz(n): > r=[] > while n>1: > r.append(n) > n = 3*n+1 if n%2 else n/2 > yield r > > for i, x in enumerate(collatz(13)): > try: > last = x[:i+1] > print x[:i+1] > except StopIteration: > print last.appnd(1) > > Output: > [13] > [13, 40] > [13, 40, 20] > [13, 40, 20, 10] > [13, 40, 20, 10, 5] > [13, 40, 20, 10, 5, 16] > [13, 40, 20, 10, 5, 16, 8] > [13, 40, 20, 10, 5, 16, 8, 4] > [13, 40, 20, 10, 5, 16, 8, 4, 2] > last.appnd(1) <= [13, 40, 20, 10, 5, 16, 8, 4, 2, 1] # i want this > list
I would have thought you want this... >>> for i, x in enumerate(collatz(13)): ... last = x[:i+1] ... print x[:i+1] ... else: ... last.append(1) ... print last ... [13] [13, 40] [13, 40, 20] [13, 40, 20, 10] [13, 40, 20, 10, 5] [13, 40, 20, 10, 5, 16] [13, 40, 20, 10, 5, 16, 8] [13, 40, 20, 10, 5, 16, 8, 4] [13, 40, 20, 10, 5, 16, 8, 4, 2] [13, 40, 20, 10, 5, 16, 8, 4, 2, 1] -- Nick Craig-Wood <[EMAIL PROTECTED]> -- http://www.craig-wood.com/nick -- http://mail.python.org/mailman/listinfo/python-list
