On Jun 17, 5:50 am, [EMAIL PROTECTED] wrote:
> I'm writing to see calcuration process.
> And so, I can't catch StopIteration...
>
> What is mistake?
>
> def collatz(n):
> r=[]
> while n>1:
> r.append(n)
> n = 3*n+1 if n%2 else n/2
> yield r
>
> for i, x in enumerate(collatz(13)):
> try:
> last = x[:i+1]
> print x[:i+1]
> except StopIteration:
> print last.appnd(1)
>
> Output:
> [13]
> [13, 40]
> [13, 40, 20]
> [13, 40, 20, 10]
> [13, 40, 20, 10, 5]
> [13, 40, 20, 10, 5, 16]
> [13, 40, 20, 10, 5, 16, 8]
> [13, 40, 20, 10, 5, 16, 8, 4]
> [13, 40, 20, 10, 5, 16, 8, 4, 2]
> last.appnd(1) <= [13, 40, 20, 10, 5, 16, 8, 4, 2, 1] # i want this
> list
def collatz(n):
r=[]
while n>1:
r.append(n)
n = 3*n+1 if n%2 else n/2
yield r
i = 1
while 1:
try:
last = x[:i]
print x[:i]
i += 1
except StopIteration
last.append(1)
break
You will have to control the for loop yourself otherwise the
StopIteration is handled for you.
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