I am using GUI, Tkinter to be exact. But regardless of how the path gets there, it needs to opened correctly. The problem I am running into is that the program receives a path of a file, either .wma or .mp3 and is supposed to open it. I run into problems when there is either a ")" or a number next to the backslash "\" in the file path. I am looking for a way to make it work with a variable, I can make it work when I physically type it in, but not with a variable that holds the path.
Mike Driscoll wrote: > > On Jun 10, 1:57 pm, Alexnb <[EMAIL PROTECTED]> wrote: >> That would work, but not for what I want. See the file could be anywhere >> on >> the user's system and so the entire path will be unique, and that didn't >> work with a unique path. What is the subprocess module you are talking >> about? >> > > > <snip> > > As Carsten pointed out, we don't really know what you're doing. Or at > least, I don't. Why do you even want to do string substitution? How > does the user navigate to the files that the user wants to open? Are > you using a GUI or a command line interface? > > Anyway, Google is your friend. Searching for "python subprocess" gives > you this: > > http://docs.python.org/lib/module-subprocess.html > > Mike > -- > http://mail.python.org/mailman/listinfo/python-list > > -- View this message in context: http://www.nabble.com/problems-with-opening-files-due-to-file%27s-path-tp17759531p17767518.html Sent from the Python - python-list mailing list archive at Nabble.com. -- http://mail.python.org/mailman/listinfo/python-list
