maybe try string substitution... not sure if that's really the BEST way to
do it but it should work
startfile(r"%s"%variable)
--------------------------------------------------
From: "Alexnb" <[EMAIL PROTECTED]>
Sent: Tuesday, June 10, 2008 7:05 PM
To: <python-list@python.org>
Subject: Re: problems with opening files due to file's path
Well, now i've hit another problem, this time being that the path will be
a
variable, and I can't figure out how to make startfile() make it raw with
a
variable, if I put startfile(r variable), it doesn't work and
startfile(rvariable) obviously won't work, do you know how to make that
work
or better yet, how to take a regular string that is given and make every
single "\" into a double "\\"?
Mike Driscoll wrote:
On Jun 10, 11:45 am, Alexnb <[EMAIL PROTECTED]> wrote:
Gerhard Häring wrote:
> Alexnb wrote:
>> Okay, so what I want my program to do it open a file, a music file in
>> specific, and for this we will say it is an .mp3. Well, I am using
>> the
>> system() command from the os class. [...]
>> system("\"C:\Documents and Settings\Alex\My Documents\My
>> Music\Rhapsody\Bryanbros\Weezer\(2001)\04 - Island In The Sun.wma\"")
>> [...]
> Try os.startfile() instead. It should work better.
> -- Gerhard
> --
>http://mail.python.org/mailman/listinfo/python-list
No, it didn't work, but it gave me some interesting feedback when I ran
it
in the shell. Heres what it told me:
>>> os.startfile("C:\Documents and Settings\Alex\My Documents\My
>>> Music\Rhapsody\Bryanbros\Jason Mraz\I'm Yours (Single)\01 - I'm
>>> Yours.wma")
Traceback (most recent call last):
File "<pyshell#10>", line 1, in <module>
os.startfile("C:\Documents and Settings\Alex\My Documents\My
Music\Rhapsody\Bryanbros\Jason Mraz\I'm Yours (Single)\01 - I'm
Yours.wma")
WindowsError: [Error 2] The system cannot find the file specified:
"C:\\Documents and Settings\\Alex\\My Documents\\My
Music\\Rhapsody\\Bryanbros\\Jason Mraz\\I'm Yours (Single)\x01 - I'm
Yours.wma"
See it made each backslash into two, and the one by the parenthesis and
the
0 turned into an x....
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Yeah. You need to either double all the backslashes or make it a raw
string by adding an "r" to the beginning, like so:
os.startfile(r'C:\path\to\my\file')
HTH
Mike
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