On May 7, 6:13 pm, Miles <[EMAIL PROTECTED]> wrote:
(snipped)
> I think Yves meant to return [1, 3, 4, 5, 6], as in Perl's list slicing:
>
> my @x = (1, 2, 3, 4, 5, 6, 7, 8, 9, 10);
> return @x[0, 2..6]; // returns (1, 3, 4, 5, 6)
>
> This isn't incredibly efficient, but it does what you want (I think):
>
> from itertools import chain
>
> class multisliceable(list):
> def __getitem__(self, slices):
> if isinstance(slices, (slice, int, long)):
> return list.__getitem__(self, slices)
> else:
> return list(chain(*[list.__getitem__(self, s) if isinstance(s, slice)
> else [list.__getitem__(self, s)] for s in slices]))
>
> p = open('/etc/passwd')
> q = [multisliceable(e.strip().split(':'))[0,2:] for e in p]
>
> -Miles
There's also the operator module:
import itertools
import operator
idx = [one for one in itertools.chain([0], range(2, 6))]
wanted = operator.itemgetter(*idx)
q = [wanted(line.strip().split(':')) for line in file("/etc/passwd")]
--
Hope this helps,
Steven
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