One way :
>>> from functools import partial
>>> def func(item) : print item
>>> llist = [partial(func,item) for item in range(5)]
>>> for thing in llist : thing()
0
1
2
3
4
wyleu wrote:
I'm trying to supply parameters to a function that is called at a
later time as in the code below:
llist = []
for item in range(5):
llist.append(lambda: func(item))
def func(item):
print item
for thing in llist:
thing()
which produces the result
IDLE 1.2.1
================================ RESTART ================================
<function <lambda> at 0xb716356c>
<function <lambda> at 0xb71635a4>
<function <lambda> at 0xb71635dc>
<function <lambda> at 0xb7163614>
<function <lambda> at 0xb716364c>
================================ RESTART ================================
4
4
4
4
4
How can one allocate a different parameter to each instance of the
function rather than all of them getting the final value of the loop?
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