wyleu wrote: > I'm trying to supply parameters to a function that is called at a > later time as in the code below: > > llist = [] > > for item in range(5): > llist.append(lambda: func(item)) > > def func(item): > print item > > for thing in llist: > thing() > > which produces the result > > IDLE 1.2.1 >>>> ================================ RESTART >>>> ================================ >>>> > <function <lambda> at 0xb716356c> > <function <lambda> at 0xb71635a4> > <function <lambda> at 0xb71635dc> > <function <lambda> at 0xb7163614> > <function <lambda> at 0xb716364c> >>>> ================================ RESTART >>>> ================================ >>>> > 4 > 4 > 4 > 4 > 4 >>>> > > How can one allocate a different parameter to each instance of the > function rather than all of them getting the final value of the loop?
That's a FAQ. Python creates a closure for you that will retain the last value bound. To prevent that, you need to create a named paramter like this: lambda item=item: func(item) That will bind the current item value at the lambda creation time. Diez -- http://mail.python.org/mailman/listinfo/python-list
