On Sat, Apr 26, 2008 at 7:50 PM, <[EMAIL PROTECTED]> wrote:
> ok.. I finally made something that works.. Please let me know what you
> think:
>
> >>> def lines(letters):
> fin = open('words.txt')
> count = 0
> rescount = 0 # count the number of results
> results = "" # there are words that contain the letters
> for line in fin:
> needs = 0
> x = str(line.strip())
> for ch in letters:
> if ch not in x:
> pass
> else:
> needs = needs + 1
> if needs == len(letters):
> rescount += 1
> results = results + '\n' + x
> count += 1
> print count, 'lines searched'
> print results, '\n'
> print 'result count is: ', rescount
That's pretty much it.. I'm guessing you are assuming your file has
one word per line? I took a shot at it, without using the regex
module:
file = open('spyware')
my_string = 'uzi'
length = len(my_string)
words = []
for line in file :
chunks = line.strip().split()
for chunk in chunks :
x = 0
for char in my_string :
x = chunk.rfind(char,x)
if x > 0 :
words.append(chunk)
print '\n'.join(words)
or with the re module:
import re
text = open('words.txt').read()
pattern = '\S*u\S*z\S*i\S*'
stuff = re.findall(pattern,text)
count = len(stuff)
print "Found %d words :" % (count)
print "\n".join(stuff)
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