On Apr 7, 10:54 pm, BonusOnus <[EMAIL PROTECTED]> wrote:
> How do I pass a dictionary to a function as an argument?
The same way you pass any other argument.
> # Say I have a function foo...
> def foo (arg=[]):
It's generally a bad idea to use [] as a default argument.
> x = arg['name']
> y = arg['len']
>
> s = len (x)
>
> t = s + y
>
> return (s, t)
Apart from the lack of indentation (and meaningless variable names),
it looks correct.
> # The dictionary:
>
> dict = {}
> dict['name'] = 'Joe Shmoe'
> dict['len'] = 44
"dict" is a built-in name. Don't redefine it.
> # I try to pass the dictionary as an argument to a
> # function
>
> len, string = foo (dict)
Don't redefine "len" or "string" either.
> # This bombs with 'TypeError: unpack non-sequence'
>
> What am I doing wrong with the dictionary?
Runs fine for me as soon as I fixed the indentation.
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