BonusOnus wrote:
> How do I pass a dictionary to a function as an argument?
>
>
> # Say I have a function foo...
> def foo (arg=[]):
> x = arg['name']
> y = arg['len']
>
> s = len (x)
>
> t = s + y
>
> return (s, t)
I assume you actually indented the body of the function?
> # The dictionary:
>
> dict = {}
> dict['name'] = 'Joe Shmoe'
> dict['len'] = 44
'dict' is the name of a built-in type. You should name your variable
something else.
> # I try to pass the dictionary as an argument to a
> # function
>
> len, string = foo (dict)
'len' is the name of a built-in function and 'string' is a module in the
standard library. You should name both of them something else.
> # This bombs with 'TypeError: unpack non-sequence'
>
> What am I doing wrong with the dictionary?
It would be helpful to provide the full traceback, since that says what
line the problem is on...
HTH (it probably won't)
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