I was reading up on this site [http://www.noulakaz.net/weblog/
2007/03/18/a-regular-expression-to-check-for-prime-numbers/] of an
interesting way to work out prime numbers using Regular Expression.
However my attempts to use this in Python keep returning none
(obviously no match), however I don't see why, I was under the
impression Python used the same RE system as Perl/Ruby and I know the
convert is producing the correct display of 1's...Any thoughts?
def re_prime(n):
import re
convert = "".join("1" for i in xrange(n))
return re.match("^1?$|^(11+?)\1+$", convert)
print re_prime(2)
Also on a side note the quickest method I have come across as yet is
the following
def prime_numbers(n):
if n < 3: return [2] if n == 2 else []
nroot = int(n ** 0.5) + 1
sieve = range(n + 1)
sieve[1] = 0
for i in xrange(2, nroot):
if sieve[i]:
sieve[i * i: n + 1: i] = [0] * ((n / i - i) + 1)
return [x for x in sieve if x]
Damn clever whoever built this (note sieve will produce a list the
size of your 'n' which is unfortunate)
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