Boris Borcic wrote: > Arnaud Delobelle wrote: > (...) >> >> from itertools import chain >> >> def overlaps(lst): >> bounds = chain(*(((x[1],i), (x[2], i)) for i,x in enumerate(lst))) > > imho, this is a uselessly painful equivalent of > > bounds = ((x[k],i) for i,x in enumerate(lst) for k in (1,2))
even more readable :
bounds = ((bound(x),i) for bound in (min,max) for i,x in
enumerate(lst))
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