On Jan 8, 2008 6:54 AM, BJ Swope <[EMAIL PROTECTED]> wrote: > > > given a list such as > > > > > > ['messages', 'recipients', 'viruses'] > > > > > > how would I iterate over the list and use the values as variables and > > > open the variable names a files? > > > > > > I tried > > > > > > for outfile in ['messages', 'recipients', 'viruses']: > > > filename = os.path.join(Host_Path, outfile) > > > outfile = open(filename, 'w') > > > > > > But it's not working. > > Yep, defining "not working" is always helpful! :) > > I want to have all 3 files open at the same time. I will write to each of > the files later in my script but just the last file is open for writing.
Your code successfully opened them all, but kept a reference only to the last one. Try something like: outfiles = [open(os.path.join(Host_Path, fname), 'w') for fname in fnames] -- Neil Cerutti <[EMAIL PROTECTED]> -- http://mail.python.org/mailman/listinfo/python-list
