BJ Swope wrote:
> the code looks ok. please define "not working".
>
> Yep, defining "not working" is always helpful! :)
>
> I want to have all 3 files open at the same time. I will write to each
> of the files later in my script but just the last file is open for writing.
to keep more than one file open, you need more than one variable, or a
variable that can hold more than one object.
if the number of files may vary, put the file objects in a list. if the
number of files is constant, you might as well just use three variables
and call open three times; e.g.
def getfilename(name):
return os.path.join(Host_Path, name)
messages_file = open(getfilename("messages"), "w")
recipients_file = open(getfilename("recipients"), "w")
viruses_file = open(getfilename("viruses"), "w")
</F>
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