[EMAIL PROTECTED] writes:
> Is the following correct?
>
> [lots of references to "references"]
All good so far.
> x[0] += " other"
>
> Another string is created, the first element of x is modified to point
> to the new string and back outside foo(), x[0] will point to the new
> string.
Change these to talk about "references" again and it'll be true also:
"Another string is created, the first element of x now refers to
the new string and back outside foo(), x is still a reference to
the same list (so its first element is a reference to the same
string)."
> Right?
Right. In Python, all names, and all elements of container objects,
are references to the corresponding objects. Python has no concept of
"pointers" in the style of C-like languages.
--
\ "I fly Air Bizarre. You buy a combination one-way round-trip |
`\ ticket. Leave any Monday, and they bring you back the previous |
_o__) Friday. That way you still have the weekend." -- Steven Wright |
Ben Finney
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