Is the following correct? x = "some string"
x is a reference to "some string" foo(x) Reference is passed to function. In foo: x += " change" Strings are immutable, so x in foo() now points to a different string than x outside foo(). Right? Back outside foo. x = ["some string"] x is a reference to a list whose first element is a reference to a string. foo(x) Within foo: x[0] += " other" Another string is created, the first element of x is modified to point to the new string and back outside foo(), x[0] will point to the new string. Right? -- http://mail.python.org/mailman/listinfo/python-list