Donn Ingle wrote: > In an unusual twist of code I have a subclass which overrides a method but > it also needs to call the original method: > > class One: > def add (self, stuff): > self.stuff.append(stuff) > > class Two(One): > def __init__(self, otherstuff): > <MYSTERY>(otherstuff) #otherstuff must go into list within the parent. > #The override - totally different function in this context. > def add (self, data): > self.unrelated.append (data) > > For: > <MYSTERY> > I have tried: > self.One.add( otherstuff ) > No go. > super ( Two, self).add( otherstuff ) > Gives this error:TypeError: super() argument 1 must be type, not classobj > (Which reminds me, how the heck does super work? I always get that error!) > This is a typical error. You get this when you try to use "super" with old style classes. You should try it with new style classes.
See: "class One(object):" instead of "class One:". BTW you can always do a direct call: def add(self,data): One.add(self,otherstuff) and super isn't always the good thing to use. Best, Laszlo -- http://mail.python.org/mailman/listinfo/python-list