Shawn Minisall wrote: > K I've since fixed the UnboundLocalError: local variable 'ai' referenced > before assignment error, I forgot to include decision = (1, 2, 3) inside > " " for each number. > > You mean like decision = ("1", "2", "3") ? I don't think that would have caused the error you reported. You probably changed something else as well. > Now when I run it, I get this.. > > >>> main() > READY TO PLAY ROCK, PAPER, SCISSORS??? > > Please choose from the following menu: > 1. See the rules > 2. Play against the computer > 3. Play a two player game > 4. Exit > Please enter your choice here: 2 > > ===================== > you choose scissors > > I choose > > YOU LOSE! > > Rounds Won: 0 > > Rounds Lost: 1 > > Rounds Tied: 0 > > > Would you like to play again? y > Please choose from the following menu: > 1. See the rules > 2. Play against the computer > 3. Play a two player game > 4. Exit > Please enter your choice here: 2 > > Please choose a weapon from the following menu: > 1. Rock > 2. Paper > 3. Scissors > Please choose a weapon: 1 > > and then the weapon submenu repeats over and over. > > It's also like the program is ignoring > > if ai == "1": > ai = "rock" > if ai == "2": > ai = "paper" > if ai == "3": > ai = "scissors" > > since it says I choose ________ > > Lo and behold: it *is* ignoring that block. Why? Or in other words what set of conditions have to be true in order to reach that block? Which one of them is false? (Hint: Check your while loops, and your initialization variables.)
Also, Why not use decision = ('rock', 'paper', 'scissors')? Cheers, Cliff -- http://mail.python.org/mailman/listinfo/python-list