On Fri, 2007-08-03 at 17:53 -0700, James Stroud wrote: > James Stroud wrote: > > Basically, what I am trying to acomplish is to be able to do this in any > > arbitrary module or __main__: > > > > > > funcname = determined_externally() > > ModuleUser.do_something_with(AModule, funcname) > > > > > > Ideally, it would be nice to leave out AModule if the functions were > > designed in the same namespace in which do_something_with is called. > > > Is this the preferred way? > > > import sys > def do_something_with(funcname, amodule=None): > if amodule is None: > function = sys._getframe(1).f_locals[funcname] > else: > function = getattr(amodule, funcname) > [etc.]
This seems to confirm my suspicion that the do_something_with function doesn't actually need a reference to the module, it only needs a reference to the function to call. Maybe your hurdle is how to obtain a reference to a function from the current module when all you have is the name of the function in a string. The answer to that would be "globals()[funcname]". -- Carsten Haese http://informixdb.sourceforge.net -- http://mail.python.org/mailman/listinfo/python-list
