On Fri, 13 Jul 2007 11:30:16 -0700, Paul McGuire <[EMAIL PROTECTED]>
wrote:
>On Jul 13, 1:20 pm, Wayne Brehaut <[EMAIL PROTECTED]> wrote:
>> On Mon, 09 Jul 2007 23:51:25 -0700, "[EMAIL PROTECTED]"
>>
>>
>>
>>
>>
>> <[EMAIL PROTECTED]> wrote:
>> >On Jul 9, 11:42?pm, Paul McGuire <[EMAIL PROTECTED]> wrote:
>> >> On Jul 9, 11:21 pm, "Jim Langston" <[EMAIL PROTECTED]> wrote:> In Python
>> >> 2.5 on intel, the statement
>> >> > 2**2**2**2**2
>> >> > evaluates to>>> 2**2**2**2**2
>>
>> >> > 200352993040684646497907235156025575044782547556975141926501697371089405955
>> >> > 63114
>> >> > 530895061308809333481010382343429072631818229493821188126688695063647615470
>> >> > 29165
>> >> > 041871916351587966347219442930927982084309104855990570159318959639524863372
>> >> > 36720
>>
>> >> <snip>
>>
>> >> Exponentiation is right associative, so this is the same as:
>>
>> >> 2**(2**(2**(2**2)))
>> >> 2**2**2**4
>> >> 2**2**16
>> >> 2**65536
>>
>> >> 2=10**0.3010, so 2**65536 is approx 10**19726
>>
>> >> There are 19730 digits in your answer,
>>
>> >>>> import gmpy
>> >>>> n = 2**2**2**2**2
>> >>>> gmpy.numdigits(n)
>> >19729
>>
>> >Did you count the 'L'?
>>
>> numdigits(n)?
>>
>> What? 'L' is a digit in Python? I'm going back to Fortran!
>>
>> wwwayne
>>
>>
>>
>> >>so this seems to be at least in
>> >> the ball park.
>>
>> >> -- Paul- Hide quoted text -
>>
>> - Show quoted text -- Hide quoted text -
>>
>> - Show quoted text -
>
>'L' counts for 50, but only when you use Roman font.
WTL?! Not Times New Roman I hope?
Now I'll have to extend my remarks below to include:
L**L**L
D**D**D
M**M**M
etc. (since I don't recall what comes next)
though these (L, D, M, ...) would seem to be numbers rather than
digits: the Romans used a base-1 system [for purposes of this
argument, at least] so I is the only Roman digit* and the others are
just shorthand for:
I = 1
V = IIIII
X = I*10
L = I*50
D = I*500
M = I*1000
etc.
---
For those who don't know which Roman digit I represents:
|
_\|/__
wwwayne
>
>-- Paul
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