Consider this example: >>> def funcs(x): ... for i in range(5): ... def g(): return x + i ... yield g
I would expect the value of x used in g to be that at the function declaration time, as if you've pass g a (x=x) argument, especially after reading this post: http://lua-users.org/wiki/LuaScopingDiscussion But: >>> [ fun() for fun in list(funcs(1)) ] [5, 5, 5, 5, 5] Whereas: >>> [ fun() for fun in funcs(1) ] [1, 2, 3, 4, 5] This came up while discussing Python pain points at http://intertwingly.net/blog/2007/06/04/Python-Pain-Points#c1181602242 I can see how it works now, but I haven't found an easy-to-read documentation on this. I guess it's debatable if perhaps every i used in the loop shouldn't be a different i. It had me fooled, anyways. Rgds, Bjorn -- http://mail.python.org/mailman/listinfo/python-list
