Beorn wrote: > Consider this example: > > >>> def funcs(x): > ... for i in range(5): > ... def g(): return x + i > ... yield g > > I would expect the value of x used in g to be that at the function
You mean i here, don't you? > declaration time, as if you've pass g a (x=x) argument, especially > after reading this post: http://lua-users.org/wiki/LuaScopingDiscussion > > But: > > >>> [ fun() for fun in list(funcs(1)) ] > [5, 5, 5, 5, 5] > > Whereas: > > >>> [ fun() for fun in funcs(1) ] > [1, 2, 3, 4, 5] > > This came up while discussing Python pain points at > http://intertwingly.net/blog/2007/06/04/Python-Pain-Points#c1181602242 > > I can see how it works now, but I haven't found an easy-to-read > documentation on this. This has been discussed here very often. Python closures do capture the names, not the values. If you want a value at a certain point, you need to bind in the generated function scope by passing it as parameter. Like this: def funcs(x): for i in xrange(5): def g(i=i): return x + i yield g Diez -- http://mail.python.org/mailman/listinfo/python-list
