> >>> [] == False > False > > Could anybody point out why this is the case?
Writing, "if x" is short for writing "if bool(x)". Evaluating bool(x) checks for a x.__nonzero__() and if that method isn't defined, it checks for x.__len__() to see if x is a non-empty container. In your case, writing "if []" translates to "if len([]) != 0", which evaluates to False. True and False are of type bool which is a subclass of int. So, False really is equal to zero and True really is equal to one. In contrast, the empty list is not of type int. So [] != False eventhough bool([]) == False. Raymond -- http://mail.python.org/mailman/listinfo/python-list
