Hello all, I'm having trouble understanding why the following code evaluates as it does:
>>> string.find('0200000914A','.') and len('0200000914A') > 10 True >>> len('0200000914A') > 10 and string.find('0200000914A','.') -1 In the 2.4 Python Reference Manual, I get the following explanation for the 'and' operator in 5.10 Boolean operations: " The expression x and y first evaluates x; if x is false, its value is returned; otherwise, y is evaluated and the resulting value is returned." Based on what is said above, shouldn't my first expression ( string.find('0200000914A','.') and len('0200000914A') > 10) evaluate to false b/c my 'x' is false? And shouldn't the second expression evaluate to True? Thanks for your help Greg -- View this message in context: http://www.nabble.com/Boolean-confusion-tf3715438.html#a10393362 Sent from the Python - python-list mailing list archive at Nabble.com. -- http://mail.python.org/mailman/listinfo/python-list