Thank you Diez and Antoon for demystifing this problem. I see where I've been
going wrong.
Diez B. Roggisch-2 wrote:
>
> Greg Corradini wrote:
>
>>
>> Hello all,
>> I'm having trouble understanding why the following code evaluates as it
>> does:
>>
>>>>> string.find('0200000914A','.') and len('0200000914A') > 10
>> True
>>>>> len('0200000914A') > 10 and string.find('0200000914A','.')
>> -1
>>
>> In the 2.4 Python Reference Manual, I get the following explanation for
>> the 'and' operator in 5.10 Boolean operations:
>> " The expression x and y first evaluates x; if x is false, its value is
>> returned; otherwise, y is evaluated and the resulting value is returned."
>>
>> Based on what is said above, shouldn't my first expression (
>> string.find('0200000914A','.') and len('0200000914A') > 10) evaluate to
>> false b/c my 'x' is false? And shouldn't the second expression evaluate
>> to
>> True?
>
> The first evaluates to True because len(...) > 10 will return a boolean -
> which is True, and the semantics of the "and"-operator will return that
> value.
>
> And that precisely is the reason for the -1 in the second expression.
>
> y=-1
>
> and it's just returned by the and.
>
> in python, and is implemented like this (strict evaluation
> nonwithstanding):
>
> def and(x, y):
> if bool(x) == True:
> return y
> return x
>
> Diez
> --
> http://mail.python.org/mailman/listinfo/python-list
>
>
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