On Apr 4, 11:20 am, "7stud" <[EMAIL PROTECTED]> wrote: > On Apr 4, 10:55 am, "Terry Reedy" <[EMAIL PROTECTED]> wrote: > > > <[EMAIL PROTECTED]> wrote in message > > >news:[EMAIL PROTECTED] > > | For any list x, x.index(item) returns the index of the FIRST > > | occurrence of the item in x. Is there a simple way to identify the > > | LAST occurrence of an item in a list? My solution feels complex - > > | reverse the list, look for the first occurence of the item in the > > | reversed list, and then subtract its index from the length of the list > > | - 1, i.e. > > | > > | LastOcc = len(x) - 1 - x[::-1].index(item) > > | > > | Is there a simpler solution? > > How about: > > l = [1, 2, 1, 3, 1, 5] > target = 1 > for index, val in enumerate(l): > if val==1: > lastIndexOf = index > > print lastIndexOf
Nahh. Horrible solution. You should start at the end of the list. -- http://mail.python.org/mailman/listinfo/python-list
