On 4 Apr 2007 08:58:49 -0700, [EMAIL PROTECTED] <[EMAIL PROTECTED]> wrote: > For any list x, x.index(item) returns the index of the FIRST > occurrence of the item in x. Is there a simple way to identify the > LAST occurrence of an item in a list? My solution feels complex - > reverse the list, look for the first occurence of the item in the > reversed list, and then subtract its index from the length of the list > - 1, i.e. > > LastOcc = len(x) - 1 - x[::-1].index(item) > > Is there a simpler solution?
Simpler ? That's subjective. :) You definitely need to search/iterate a reversed list, or start from the far end of a non-reversed list. For fun only. >>> t = [0,1,2,3,0] >>> def place(t,i): ... for x,y in zip(t,range(len(t)))[::-1]: ... if x == i: ... return y ... >>> place(t,3) 3 >>> place(t,0) 4 -- http://mail.python.org/mailman/listinfo/python-list
