On Mar 26, 2007, at 7:00 AM, sandeep patil wrote:
> i have written this program but i have gott following error,
> in anather proram "indentation error" sir how i will indent in my
> editor
>
> #test.py
>>>> def invert(table):
> index=()
> for key in table:
> value=table[key]
> if not index.has_key(value):
> index[value]=[]
> index[value].append(key)
> return index
>
>
>>>> phonebook = {'sandeep':9325, 'amit':9822, 'anand':9890, 'titu':
>>>> 9325}
>>>> phonebook
> {'titu': 9325, 'amit': 9822, 'anand': 9890, 'sandeep': 9325}
>>>> print phonebook
> {'titu': 9325, 'amit': 9822, 'anand': 9890, 'sandeep': 9325}
>>>> inverted_phonebook = invert(phonebook)
>
> Traceback (most recent call last):
> File "<pyshell#13>", line 1, in <module>
> inverted_phonebook = invert(phonebook)
> File "<pyshell#9>", line 5, in invert
> if not index.has_key(value):
> AttributeError: 'tuple' object has no attribute 'has_key'
If you define index as a dict instead of a tuple, you'll stop getting
that error -- but I'm afraid it still won't do what you want. Are
you trying to get a phonebook in which the values of the original
phonebook are the keys of the new one -- and the values are lists
(both 'sandeep' and 'titu' have the same number)? If so, try this:
def invert(table):
index=dict()
for k,v in table.items():
if index.has_key(v):
index[v].append(k)
else:
index[v] = [k]
return index
You had mentioned something about indentation error... If you'll
look at your definition of invert(), you can see that 'return index'
is inside the for loop -- which would cause a return before the
second time through the for loop. By dedenting (is that a word?) so
'return' falls directly below 'for', the for loop would have been
able to run to completion before returning.
Hope this helps,
Michael
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