On 25 Mar 2007 03:59:52 -0700, [EMAIL PROTECTED] wrote: >Hello, > >when I execute the following code (python 2.5) > >def f(x): > def g(): > return x > return g > >print f(1) >print f(2) > >I get an output like > ><function g at 0x00AFC1F0> ><function g at 0x00AFC1F0> > >So according to print I get the same function object returned at both >calls. >That's surprising, I would expect to get two distinct function objects >because their func_closure attribute has to be different. And indeed, >if I do > >print f(1) is f(2) > >instead, it prints False. Even more confusing, if I do > >g1 = f(1) >g2 = f(2) >print g1 >print g2 > >I get something like > ><function g at 0x00AFC1B0> ><function g at 0x00AFC1F0> > >ie. two distinct function objects are printed. > >What's happening here? >Some clever optimization reusing function objects in special cases or >what ...?
They're _not_ the same function object, just like the `is' test told you. They just happen to have been allocated at the same memory address. Jean-Paul -- http://mail.python.org/mailman/listinfo/python-list
