Steven Bethard wrote: > Is there a good way to determine if an object is a numeric type? Generally, I > avoid type-checks in > favor of try/except blocks, but I'm not sure what to do in this case: > > def f(i): > ... > if x < i: > ... > > The problem is, no error will be thrown if 'i' is, say, a string: > > py> 1 < 'a' > True > py> 10000000000 < 'a' > True > > But for my code, passing a string is bad, so I'd like to provide an > appropriate error.
assert operator.isNumberType(i) (but make sure you read the warning in the docs: http://docs.python.org/lib/module-operator.html ) </F> -- http://mail.python.org/mailman/listinfo/python-list
