Re: check if object is number

[marco]

Steven Bethard wrote:
Is there a good way to determine if an object is a numeric type? 
.
.
.
Ideas?
Maybe this can help?
def isnumber(x):
    try:
        return(x == x-0)
    except:
        return False
print '1:\t', isnumber(1)
print '1.25:\t', isnumber(1.25)
print '1.0 / 7:\t', isnumber(1.0 / 7)
print '1+0j:\t', isnumber((1+0j))
print '"spam":\t', isnumber("spam")
output:
1:      True
1.25:   True
1.0/7:  True
1+0j:   True
"spam":       False
Ooops! While checking other posts I realized that this is almost the 
same as Dan Bishop's solution.

Marco
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