Steven Bethard wrote: > Is there a good way to determine if an object is a numeric type? > Generally, I avoid type-checks in favor of try/except blocks, but I'm
> not sure what to do in this case: > > def f(i): > ... > if x < i: > ... > > The problem is, no error will be thrown if 'i' is, say, a string: > > py> 1 < 'a' > True > py> 10000000000 < 'a' > True > > But for my code, passing a string is bad, so I'd like to provide an > appropriate error. > > I thought about calling int() on the value, but this will also allow > some strings (e.g. '1'). I guess this isn't horrible, but it seems > somewhat suboptimal... How about this? ... def is_number(x): ... try: ... x + 1 ... return True ... except TypeError: ... return False -- http://mail.python.org/mailman/listinfo/python-list
