"Steven Bethard" <[EMAIL PROTECTED]> wrote in message
news:[EMAIL PROTECTED]
> Is there a good way to determine if an object is a numeric type?
> Generally, I avoid type-checks in favor of try/except blocks, but I'm
> not sure what to do in this case:
>
> def f(i):
> ...
> if x < i:
> ...
>
> The problem is, no error will be thrown if 'i' is, say, a string:
>
> py> 1 < 'a'
> True
> py> 10000000000 < 'a'
> True
>
> But for my code, passing a string is bad, so I'd like to provide an
> appropriate error.
>
> I thought about calling int() on the value, but this will also allow
> some strings (e.g. '1'). I guess this isn't horrible, but it seems
> somewhat suboptimal...
>
> Ideas?
>
> Steve
The thing is that python avoids giving a strict definition of what is a
'numeric type', i.e. a
well-defined interface (the same holds for other frequently used interfaces
such as 'sequence',
'mapping', 'file-like', etc). It's up to you (the user) to think of all the
operations you
anticipate to be supported by each argument, attribute, etc. and define a
'numeric type checker' (or
even better, adaptor) that suits *your application*. In your example, what does
your application
consider to be numeric ? Strings are definitely not, integers and floats
typically are; on the other
hand, complex numbers are usually not expected, even though mathematically they
are 'numeric'. In
this case, you can write something like:
def isNumeric(obj):
# consider only ints and floats numeric
return isinstance(obj,int) or isinstance(obj,float)
The bottom line is that python wisely doesn't enforce any universal numeric
type ("in the face of
ambiguity, refuse the temptation to guess").
George
--
http://mail.python.org/mailman/listinfo/python-list
