Steven D'Aprano wrote: > On Sat, 03 Mar 2007 23:22:10 +0000, James Stroud wrote: > >>> To my mind, having to supply a key to dict.pop makes it rather pointless. >>> >>> >> >> I've used it in something like this and found it worthwhile: >> >> for akey in dict1: >> if some_condition(akey): >> dict2[akey] = dict2.pop(akey) > > Surely that's a no-op? You pop the value, than add it back again. > > Or do you mean dict2[akey] = dict1.pop(akey)? > > If so, are you sure that works? When I try it, I get "RuntimeError: > dictionary changed size during iteration". You would need to take a copy > of the keys and iterate over that. > > for key in dict1.keys(): > if some_condition(key): > dict2[key] = dict1.pop(key) > > >
Yes. You are right, both in the typo and using keys(). James -- http://mail.python.org/mailman/listinfo/python-list
