On Sat, 03 Mar 2007 23:22:10 +0000, James Stroud wrote:
>> To my mind, having to supply a key to dict.pop makes it rather pointless.
>>
>>
>
>
> I've used it in something like this and found it worthwhile:
>
> for akey in dict1:
> if some_condition(akey):
> dict2[akey] = dict2.pop(akey)
Surely that's a no-op? You pop the value, than add it back again.
Or do you mean dict2[akey] = dict1.pop(akey)?
If so, are you sure that works? When I try it, I get "RuntimeError:
dictionary changed size during iteration". You would need to take a copy
of the keys and iterate over that.
for key in dict1.keys():
if some_condition(key):
dict2[key] = dict1.pop(key)
--
Steven.
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