[EMAIL PROTECTED] wrote:
> Hi, I have the following functions,  but ' dx = abs(i2 - i1)/min(i2,
> i1)' always return 0, can you please tell me how can i convert it from
> an integer to float?

When two integers are involved in a division, the result will also be a 
division. If one of the operands is a float, then the result will be a 
float instead. So try casting one of the values to a float before 
performing the division:

dx = float(abs(i2 - i1))/min(i2, i1)

-Farshid
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