On 2007-03-05, Andrew Koenig <[EMAIL PROTECTED]> wrote: ><[EMAIL PROTECTED]> wrote in message > news:[EMAIL PROTECTED] >> Hi, I have the following functions, but ' dx = abs(i2 - i1)/min(i2, >> i1)' always return 0, can you please tell me how can i convert it from >> an integer to float? > > I don't think that's what you really want to do. > > What you really want is for dx to be a float rather than being truncated to > an integer. Division is going to behave that way in the future, so if you > want it to behave that way now, you can write > > from __future__ import division > > at the beginning of your program. > > If for some reason you don't want to rely on using a version of Python that > knows about this future behavior, you might consider > > dx = float(abs(i2 - i1))/min(i2, i1)
I prefer to multiply by 1.0 That has the advantage it continues to work if your numbers happen to be complex. -- Antoon Pardon -- http://mail.python.org/mailman/listinfo/python-list
