On Feb 26, 8:03 pm, "funkyj" <[EMAIL PROTECTED]> wrote:
> I want to call os.path.join() on a list instead of a variable list of
> arguments. I.e.
>
> [scr-misc] (186:0)$ python
> iPython 2.4 (#2, Feb 18 2005, 16:39:27)
> [GCC 2.95.4 20020320 [FreeBSD]] on freebsd4
> Type "help", "copyright", "credits" or "license" for more
> information.
> m>>>
> >>> import os
> >>> import string
> >>> p = os.environ['PWD']
> >>> p
> '/tmp/a/b/c/d'
> >>> os.path.join(string.split(p, os.sep))
> ['', 'tmp', 'a', 'b', 'c', 'd']
> >>>
>
> the value returned by os.path.join() is obviously not the desired
> result ...
>
> Sure, I can hack my own version of os.path.join() by using os.sep but
> that does not seem very pythonic.
>
> In lisp one would do something like
>
> (funcall #'os.path.join (string.split p os.sep))
>
> What is the python idiom for callling a function like os.path.join()
> that takes a variable number of arguments when you currently have the
> arguements in a list variable?
>
> I'm curious about the answer to the question above but in the meantime
> I'll hack "my.path.join()' that takes a single list as an argument and
> move on with my little project.
>
> Regards,
> fj
figured it out ...
I can just do:
os.sep.join(string.split(p, os.sep))
it isn't "funcall" but it gets me where I want to go.
Regards,
--jfc
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