I want to call os.path.join() on a list instead of a variable list of
arguments. I.e.
[scr-misc] (186:0)$ python
iPython 2.4 (#2, Feb 18 2005, 16:39:27)
[GCC 2.95.4 20020320 [FreeBSD]] on freebsd4
Type "help", "copyright", "credits" or "license" for more
information.
m>>>
>>> import os
>>> import string
>>> p = os.environ['PWD']
>>> p
'/tmp/a/b/c/d'
>>> os.path.join(string.split(p, os.sep))
['', 'tmp', 'a', 'b', 'c', 'd']
>>>
the value returned by os.path.join() is obviously not the desired
result ...
Sure, I can hack my own version of os.path.join() by using os.sep but
that does not seem very pythonic.
In lisp one would do something like
(funcall #'os.path.join (string.split p os.sep))
What is the python idiom for callling a function like os.path.join()
that takes a variable number of arguments when you currently have the
arguements in a list variable?
I'm curious about the answer to the question above but in the meantime
I'll hack "my.path.join()' that takes a single list as an argument and
move on with my little project.
Regards,
fj
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