yeah! that's easy! althought no so clear a = lambda x,y:(x,y) b = lambda y:a(1,y)
a(1,2) (1,2) b(2) (1,2) On 1月17日, 下午12时10分, Alejandro Dubrovsky <[EMAIL PROTECTED]> wrote: > kernel1983 wrote: > > In Function Program?Language can use like this: > > > define a function: > > f = lambda x,y:x,y > > > then we use f to define another function: > > f2 = f(1) > > the f2 should equal to: > > f2=lambda y:1,y > > > we should be able call f2 with one parameter:f2(2) > > just return 1,2 > > > but how can I implement the characteristic in Python??I think it could > > do like this but HOW-TO?If you are using python 2.5, then you can use > > functools.partial, otherwise > lookup one of the many curry implementations, like the ones found > inhttp://aspn.activestate.com/ASPN/Cookbook/Python/Recipe/52549 > > One found in the comments of that page by Scott David Daniels: > > def curry(*args, **kwargs): > function, args = args[0], args[1:] > def result(*rest, **kwrest): > combined = kwargs.copy() > combined.update(kwrest) > return function(*args + rest, **combined) > return result > > so, in your case: > > f = lambda x,y: (x,y) > f2 = functools.partial(f,1)>>> f2(3)1,3
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