George Sakkis wrote:
> Meet itertools:
>
> from itertools import chain
> names = set(chain(*r.itervalues()))
> print [line for line in table if line[7] in names]
Steven D'Aprano wrote:
> Assuming you don't care what order the strings are in:
>
> r = {'a':('ASLIB','Aslib'),'j':('JDOC','jdoc')}
> result = sum(r.values(), ())
>
> If you do care about the order:
>
> r = {'a':('ASLIB','Aslib'),'j':('JDOC','jdoc')}
> keys = r.keys()
> keys.sort()
> result = []
> for key in keys:
> result.extend(r[key])
> result = tuple(result)
Thank you everybody.
As it is possible that the tuples will not always be the same word in
variant cases
result = sum(r.values(), ())
will do fine and is as simple as I suspected the answer would be.
--
djc
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